一般には，
$\theta+\dfrac{\pi}{3} = \dfrac{\pi}{4}+n\pi$   (n は整数)

すなわち，
$\theta = \dfrac{-1+12n}{12}\pi$   (n は整数)

0 ≦ θ < 2π では，
$\theta = \dfrac{11}{12}\pi$,  $\dfrac{23}{12}\pi$  

一般には，
$\dfrac{\pi}{4}+n\pi < \theta+\dfrac{\pi}{3}$ $< \dfrac{\pi}{2}+n\pi$   (n は整数)

すなわち，
$\dfrac{-1+12n}{12}\pi < \theta$ $< \dfrac{1+6n}{6}\pi$   (n は整数)

0 ≦ θ < 2π では，
$0\leqq \theta < \dfrac{\pi}{6}$,   $\dfrac{11}{12}\pi < \theta < \dfrac{7}{6}\pi$,   $\dfrac{23}{12}\pi < \theta < 2\pi$  

一般には，
$-\dfrac{\pi}{2}+n\pi < \theta+\dfrac{\pi}{3}$ $< \dfrac{\pi}{4}+n\pi$   (n は整数)

すなわち，
$\dfrac{-5+6n}{6}\pi < \theta$ $< \dfrac{-1+12n}{12}\pi$   (n は整数)

0 ≦ θ < 2π では，
$\dfrac{\pi}{6} < \theta < \dfrac{11}{12}\pi$,   $\dfrac{7}{6}\pi < \theta < \dfrac{23}{12}\pi$